robinson.py

Created on April 14, 2018

396 Bytes

Calcule les termes de la suite de Robinson jusqu’à obtenir une boucle.

Essayez robinson(“0”) ou robinson(“40”).

def robinson(string):
  print(0,string)
  count=0
  sequence=[string]

  while True:
    string="".join("%d%d"%(string.count(str(digit)),digit) for digit in range(9,-1,-1) if string.count(str(digit)))
    if string in sequence:
      print("Repetition of %s at #%d"%(string,sequence.index(string)))
      break
    count+=1
    sequence+=[string]
    print("%d %s"%(count,string))